As Paper 1 Mark Scheme Paper 1 Pure Mathematics M Uses ax by k = 0 and substitutes both x = 3 when y = 1 and x = 4 when y = 2 with attempt to solve to find a, b or k in terms of one of them m1 1.1b obtains a = 3b, k = 10b or 3k = 10a a1 1.1b obtains a = 3, b = 1, k = 10 or writes 3x y – 10 = 0 o.e. a1 1.1b (3) (3 marks) notes m1: need correct use of the given coordinates a1: need. A1*: multiplies by x (the processed line must be seen) and proceeds to given answer with no slips. condone if the order of the terms are different 2 x 2 k 2 4 x 0. (c) m1: deduces that b 2 4 ac 0 or equivalent for the given equation. if a, b and c are stated only accept a 2, b 4, c k.
Pdf Paper 1 Pure Mathematics Mark Scheme Maths Genie в Qu Dm1: correct method to find one value of θ from their 2 θ ± α° = 79.1 ° to θ = 79.1 . 2. this is dependent upon one angle being correct, which must be in degrees, for arctan ( 3 3 ) tan ( 2 θ 60 ° ) = 3 3 ⇒ θ = 9.6 ° would imply b1 m1 dm1. a1: θ = awrt 9.6 ° , 99.6 ° with no other values given in the range. L marking guidance all candidates must receiv. the same treatment. examiners must mark the last candidate in exactly the same way as. y mark the first. mark schemes should b. applied positively. candidates must be rewarded for what they have shown they can do rather than pen. ed for omissions. examiners should mark according to the mark scheme. Sets line = curve, multiplies by (2 − x ) , attempts to expand and collects terms on one side of the equation. condone the absence of =0. a1 correct equation unsimplified with all terms on one side, condone the absence of =0. this may be implied by later work such as their values of a, b and c substituted in to b. 14 xy . 2 y 3432 reaching an equation of the form. 4 2 ay by c 0. alt. m1 (a1 on epen) 4 2 for an attempt to solve their equation of the form ay by c 0 as a quadratic in y2 (minimally acceptable attempt to solve, see general guidance) (a fully correct solution would give: y. 2 .
A Level Edexcel Pure Mathematics Paper 1 Mark Scheme 2022a Level Sets line = curve, multiplies by (2 − x ) , attempts to expand and collects terms on one side of the equation. condone the absence of =0. a1 correct equation unsimplified with all terms on one side, condone the absence of =0. this may be implied by later work such as their values of a, b and c substituted in to b. 14 xy . 2 y 3432 reaching an equation of the form. 4 2 ay by c 0. alt. m1 (a1 on epen) 4 2 for an attempt to solve their equation of the form ay by c 0 as a quadratic in y2 (minimally acceptable attempt to solve, see general guidance) (a fully correct solution would give: y. 2 . 1 as pure mathematics 8ma0: specimen paper 1 mark scheme question scheme marks aos 1 (a) 22d d y x x m1 a1 1.1b 1.1b (2) (b) attempts 0xx2!!0xx m1 1.1b 1 1 3 x , a1 1.1b chooses outside region m1 1.1b 1 ^ 1` 3 x x x x ½ ®¾ ! ¯¿:: a1 2.5 (4) (6 marks) notes: (a) m1: attempts to differentiate. allow for two correct terms un simplified. M1: uses n = 1 and n = 2 to identify values for m1: starts the induction process by adding the. a and b. (k 1)th term to the sum of k terms a1: correct single fraction m1: attempt to factorise the numerator a1: correct answer and conclusion. main scheme. m1: valid attempt at partial fractions m1: starts the process of differences to identify.
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